SURFACE AREAS AND VOLUMES
EXERCISE 12.1
Q1: 2 cubes, each of volume 64 cm^3, are joined end to end. Find the surface area of the
resulting cuboid.
Solution:
Volume of one cube = X3
Side of one cube = (X3)1/3
If we join two cubes,
then it will form a cuboid.
Then the length
of the cuboid = 4 cm + 4cm = 8cm.
Height of the
cuboid = 4cm
Width = 4cm
Therefore, the
total surface area of the cuboid = 2(lb + b*h + h*l)
=2*(8*4
+4*4+4*8)
= 2*(32 + 16 + 32)
=
160 cm2
2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The
diameter of the hemisphere is 14 cm, and the total height of the vessel is 13 cm. Find the
inner surface area of the vessel.
Solution
Diameter of
hemisphere = 2r = 14cm
Radius = 14/2 =
7cm
Total height of
the container = 13cm
Height of the cylindrical
part = 13-7 cm = 6cm
Inner surface
area total = curved surface area of hemisphere curved surface area of cylinder
= 2∏r + 2∏rh = 2∏r(r + h)
= 2*(22/7)*7(7+6)
= 2 * 22 * 13 = 2 * 286
= 572 cm2
3. A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of the same radius.
The total height of the toy is 15.5 cm. Find the total surface area of the toy.
Solution:
Given radius of the hemisphere = 3.5 cm
Total height = 15,5 cm
Heihjt of conical part = 15,5 – 3,5 = 12cm
Slant height of cone =
Slant height l = 12.5 cm
Total surface area = curved surface area of the hemisphere Curved surface area of the cone
= 2 ∏r2+∏rl
= ∏r ( r +l)
= 2*(22/7)*3.5 * (3.5 +12.5)
= 2*11*16
= 356 cm2
4. A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest
diameter the hemisphere can have? Find the surface area of the solid.
Solution :
Greatest diameter = 2r = 7 cm
r = 3.5 cm
Total surface area = surface area of five sides of the square + (area of the square - area of the bottom of the hemisphere that covers the top of the cube + curved surface area of the hemisphere
= 2∏r2+ 6a2 - ∏(r)2
= 6a + ∏(r)²
Where ‘a is the
side of the cube.
= 6 * 7 * 7 +
(22/7)*3.5*3.5
= 294 + 38.5
= 277 cm2
5. A hemispherical depression is cut out from one face of a cubical wooden block, such
that the diameter l of the hemisphere is equal to the edge of the cube. Determine the
surface area of the remaining solid.
Diameter of the hemisphere = l
Side of the cubical block = l
Radius of the Hemisphäre = l/2
Total surface area = total surface area of the cube + Total surface area of the hemisphere - base area of the hemisphere
Question 6: A medicine capsule is in the shape of a
cylinder with two hemispheres stuck to each
of its ends (see Fig. 12.10). The length of
the entire capsule is 14 mm and the diameter
of the capsule is 5 mm. Find its surface area.

Question 7: A tent is in the shape of a cylinder surmounted by a conical top. If the height and
diameter of the cylindrical part are 2.1 m and 4 m, respectively, and the slant height of the
top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of
the canvas of the tent at the rate of 500 per m2. (Note that the base of the tent will not
be covered with canvas.)
Solution:
Question 8: From a solid cylinder, whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the
same height and same diameter is hollowed out. Find the total surface area of the
remaining solid to the nearest cm².
Solution:
Question 9: A wooden article was made by scooping
out a hemisphere from each end of a solid
cylinder, as shown in Fig. 12.11. If the
height of the cylinder is 10 cm, and its
base is of radius 3.5 cm, find the total
surface area of the cylinder.
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